x^2+18x+30=-x^2+2x+5

Solution for x^2+18x+30=-x^2+2x+5 equation:

x^2+18x+30=-x^2+2x+5

We move all terms to the left:

x^2+18x+30-(-x^2+2x+5)=0

We get rid of parentheses

x^2+x^2-2x+18x-5+30=0

We add all the numbers together, and all the variables

2x^2+16x+25=0

a = 2; b = 16; c = +25;
Δ = b2-4ac
Δ = 162-4·2·25
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{14}}{2*2}=\frac{-16-2\sqrt{14}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{14}}{2*2}=\frac{-16+2\sqrt{14}}{4}
$